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回答时间:2025-01-10 19:38
1)x^2+3√2x-2
=(x+3√2/2)^2-13/2
=(x+3√2/2)^2-(√26/2)^2
=[(x+3√2/2)+√26/2][(x+3√2/2)-√26/2]
=[x+√2(3+√13)/2][x+√2(3-√13)/2]
2)2x^2-4xy-3y^2
=2x^2-4xy+2y^2]-5y^2
=[√2(x-y)]^2-(√5y)^2
=[√2(x-y)+√5y][√2(x-y)-√5y]
=[√2x+(√5-√2)y][√2x-(√5+√2)y]
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