作图AC延长线到E,使得AE⊥BE于E点
令CD为X1,AC为Y1,AE为Y2,BE为X2
tanA=X1/Y1=X2/Y2
∵BC=AD
∴ (Y2-Y1)^2+X2^2=Y1^2+X1^2
(0.382Y2)^2+X2^2=(0.618X2)^2+(0.618Y2)^2
X2^2-(0.618X2)^2=(0.618Y2)^2-(0.382Y2)^2
X2^2-0.382X2^2=0.382Y2^2-0.146Y2^2
0.618X2^2=0.236Y2^2
X2^2/Y2^2=0.382
∴tanA=X2/Y2=0.618
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补充:
0.618^2=1-0.618=0.382
0.382^2=0.618-0.382=0.236
0.236^2=0.382-0.236=0.146
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